please help asap ..... thermodynamics
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Answered by
1
Answer:
ur ans is 6p•v•
(3p•-p•)x(5v•-2v•)
2p.x3v. = 6p.v.
Answered by
0
Answer:
Here is the answer
Explanation:
Work done in the given process is the area under the graph
So as we can see the area of the graph = area of the rectangle
W= 3p₀-P₀ₓ 5V₀-2V₀
=2P₀ₓ 3V
= 6P₀V₀
So the answer is option (3)
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