Question

PLEASE HELP ASAP WILL GIVE BRAINLIEST!!! An observer (O) spots a plane flying at a 55° angle to his horizontal line of sight. If the plane is flying at an altitude of 21,000 feet, what is the distance (x) from the plane (P) to the observer (O)? A.20,793 ft B.25,636 ft C.28,793 ft D.36,585 ft

Answer 1

Answer:

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Step-by-step explanation:

B.25,636 ft is the correct answer

in the triangle

sin55° = 21000/x

x≈25,636

Answer 2

ANSWER:

B. 25636 ft

STEP-BY-STEP EXPLANATION:

From the given right triangle,

The Observer is at the point O and he observes the plane flying at point P.

Angel of elevation of the plane is 55° and altitude of the plane was 21000 ft.

To get the distance OP we will apply Sine rule in the given right triangle,

Sin 55 =

Sin 55 =

x =

x = 25636.27

x ≈ 25636 ft

Therefore, the distance between the plane and the observer is 25636 ft.

Option B. is the answer

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