Question

Please help bein timed!

What is the additive inverse of the polynomial –9xy2 + 6x2y – 5x3?

–9xy2 – 6x2y + 5x3
–9xy2 – 6x2y – 5x3
9xy2 + 6x2y + 5x3
9xy2 – 6x2y + 5x3

Answer 1

Answer:

You have the polynomial f(x,y)=-9xy^2 + 6x^2y - 5x^3f(x,y)=−9xy2+6x2y−5x3 .

The additive inverse of a polynomial f(x,y) is a polynomial that makes zero when it added to polynomial f(x,y). So additive inverse of polynomial f(x,y) will be -f(x,y).

Thus, the additive inverse will be

-f(x,y)=9xy^2-6x^2y+5x^3−f(x,y)=9xy2−6x2y+5x3 .

Answer 2

Given: polynomial –9xy²+ 6x²y – 5x²

To Find : additive inverse of the polynomial

-9xy² - 6x²y + 5x³

-9xy² - 6x²y - 5x³

9xy² + 6x²y + 5x³

9xy² - 6x²y + 5x³

Solution:

additive inverse of a polynomial when added to the polynomial then result is Zero

Sum of a polynomial and its additive inverse is ZERO

Assume that    Z(x, y) is Additive inverse of the given polynomial –9xy²+ 6x²y – 5x²

Hence

Z(x, y) + –9xy²+ 6x²y – 5x³  = 0

=> Z(x, y)  = - (–9xy²+ 6x²y – 5x³)

=> Z(x, y)  =  9xy² - 6x²y + 5x³

Correct option is 9xy² - 6x²y + 5x³

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