Please help!
But don't give unusual answers, please.
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Explanation:
a.)Two resistances are connected in series, the effective resistance is:
Req=R1+R2
Req=2+2=4Ω
b.)In the above question,A is in forward bias while B is in reverse bias.
The resistance of diode is now in series with 50Ωand100Ω resistors.(see figure)
The total resistance is hence, Req=50+50+100=200Ω (Series connection)
The current hence is I=2006=0.03A
Answered by
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Answer:
a 235/4 ohm
b 0.5 ampere
Explanation:
30 and 50ohm are in parallel the. 20+ 20 in series
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