Question

Please help

cos
2
θ+cos
2
theta.cot
2
θ=cot
2
θ​

Answer 1

Answer:

こんにちは

Taking LHS=cot2θ−cos2θ=sin2θcos2θ−cos2θ[∵cotθ=sinθcosθ]

=sin2θcos2θ−sin2θcos2θ=sin2θcos2θ(1−sin2θ)

[∵cos2θ+sin2θ=1]

=sin2θcos2θcos2θ=cot2θcos2θ=RHS

お役に立てば幸いです ´･ᴗ･`

Answer 2

Taking LHS=cot2θ−cos2θ=sin2θcos2θ−cos2θ[∵cotθ=sinθcosθ]

=sin2θcos2θ−sin2θcos2θ=sin2θcos2θ(1−sin2θ)[∵cos2θ+sin2θ=1]

=sin2θcos2θcos2θ=cot2θcos2θ=RHS