Question

please help don't spam please​

Answer 1

Answer:

$f(x) \: = \: \sqrt{ {2}^{x} - {3}^{x} } \\ = > put \: x = 1 \\ = > f(1) = \sqrt{2 - 3} = \sqrt{ - 1} \\ = > we \: know \: that \: i = \sqrt{ - 1} \\ = > f(1) = i \\ \\ = > x = 2 \\ = > f(2) = \sqrt{4 - 9} = \sqrt{ - 5} \\ = > f(2) = \sqrt{5} \times \sqrt{ - 1} \\ = > f(2) = i\sqrt{5} \\ \\ = > x = 3 \\ = > f(3) = \sqrt{8 - 27} = \sqrt{ - 19} \\ = > f(3) = i \sqrt{19} \\ = > and \: so \: on...$

f(x) = (i, i√5, i√19, ......)

=> so we get complex numbers in domain..

=> f(x) domain is C, where C = complex Number.