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a man saves rupees 16500 in 10 years.in each
year after the first year he saves rupees 100 more than he did in the preceding year how much did he save in the first year
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you can check answer by adding all the terms of AP and you will get 16500 as answer.
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By the given info :
a=x(let) d=100 n=10
A/Q 16500=n\2*(2à+{n-1}×d)
16500=10/2*(2*x+(10-1)*100)
16500=5×[2x+900]
3300-900=2x
So x= 2400/2
x= 1200
Therefore savings for the first year was ₹1200.
a=x(let) d=100 n=10
A/Q 16500=n\2*(2à+{n-1}×d)
16500=10/2*(2*x+(10-1)*100)
16500=5×[2x+900]
3300-900=2x
So x= 2400/2
x= 1200
Therefore savings for the first year was ₹1200.
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