Question

PLEASE HELP

DONT SPAM ​

Answer 1

Hey mate refer to the above attachment

Answer 2

if k=5

then kx+3y=k-3 become

5x+3y=2-->1

12x+ky=k becomes

12x+5y=5-->2

5 cross -->2 we get,

60x+25y=25-->A

12 cross -->1 we get,

60x+36y=24-->B

then eq A minus eq B we get

-11y=1

y=1/-11

substitute this in eq 1 we get

5x+3(1/-11)=2

5x+3/-33=2

-165x+3/-33=2

-165x+3=-66

-165x=-69

-(-165x)=-(-69)

165x=69

x=69/165

substitute x and y in kx+3y=k-3

so we get the value of k

................ :)