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Consider the recursively defined function below.
Create the first five terms of the sequence defined by the given function.
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f(1) = 10
f(n) = 2.2 f(n-1) for n = 2,3,4...
Simply taking 5 values of n as 1,2,3,4,5. We calculate f(1), f(2),.....f(5).
So, f(1) = 10 [given]
f(2) = 2.2 f(1) = 2.2 x 10 = 22
f(3) = 2.2 f(2) = 2.2 x 22 = 48.4
f(4) = 2.2 f(3) = 2.2 x 48.4 = 106.48
f(5) = 2.2 f(4) = 2.2 x 106.48 = 234.256
So, our sequence becomes:
10, 22, 48.4, 106.48, 234.256
f(n) = 2.2 f(n-1) for n = 2,3,4...
Simply taking 5 values of n as 1,2,3,4,5. We calculate f(1), f(2),.....f(5).
So, f(1) = 10 [given]
f(2) = 2.2 f(1) = 2.2 x 10 = 22
f(3) = 2.2 f(2) = 2.2 x 22 = 48.4
f(4) = 2.2 f(3) = 2.2 x 48.4 = 106.48
f(5) = 2.2 f(4) = 2.2 x 106.48 = 234.256
So, our sequence becomes:
10, 22, 48.4, 106.48, 234.256
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Answer:
Set 1 (Numeric Functions)
ceil() :- This function returns the smallest integral value greater than the number. ...
floor() :- This function returns the greatest integral value smaller than the number. ...
fabs() :- This function returns the absolute value of the number.
factorial() :- This function returns the factorial of the number.
Step-by-step explanation:
10thanks ..plzz
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