Question

please help easy not hard help me please ​

Answer 1

Answer:

first of all you should find area of whole diagram and after fine area of 2 diagram which is not shaded and minus it form whole area

I hope you will understand

if you're not understand than I'll share you full solution

Answer 2

Step-by-step explanation:

Given:

If we find the length of each side

we get a common length of 26 cm

Hence, the given fig. is of a square

Since area of square = ${s}^{2}$

Also, there are two triangle shapes in the fig..

so, we need

area of triangle = $\frac{1}{2} \times base \times height$

To find:

the area of shaded region = area of square ABCD - (area of ∆ AFE + area of ∆ EBG)

Solution:

= ${s}^{2} - (\frac{1}{2} \times AF \times AE \times ) + ( \frac{1}{2} \times EB \times BG)$

$({26})^{2} - ( \frac{1}{2} \times 8 \times 16) + ( \frac{1}{2} \times 10 \times 18) \\ = 676 - ( \frac{128}{2}) + ( \frac{180}{2} ) \\ = 676 - 64 + 90 \\ = 676 - 154 \\ = 522 \: {cm}^{2}$

The area of the shaded region is 522 cm².