Question

please help evaluate (91.5)^2using algebraic identities​

Answer 1

${\huge {\underline {\underline {\sf {Answer}}}}}$

${\underline {\underline {\rm {Given:}}}}$

• ${91.5}^{2}$

${\underline {\underline {\rm {Solution:}}}}$

Here, we will the identity ${a}^{2}$ = ${a}^{2}-2ab+{b}^{2}$

• Putting values in the Identity

$\implies{a}^{2}$

$\implies{91.5}^{2}$

• Break 91.5 and write it into a simple form

$\implies{(100-8.5)}^{2}$

• Writing it as ${a}^{2}-2ab+{b}^{2}$

$\implies100^{2}-2×100×1.5 +{8.5}^{2}$

$\implies10000-1700+72.25$

$\implies8300+72.25$

$\implies 8372.25$

Hence, at the end of the solution we get 8372.5 as our answer.

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Answer 2

Step-by-step explanation:

sorry I don't know how to do this