Math, asked by diya224, 1 year ago

please help......fast​

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Answered by 1AayushBabu
2

Answer:

-36.764

Step-by-step explanation:

= 3√32 - 2√50 + 4√128 - 20√18

= 3√2×2×2×2×2 - 2√2×5×5 +  4√2×2×2×2×2×2×2 - 20√3×3×2

= 3×2×2√2 - 2×5√2 + 4×2×2×2√2 - 20×3√2

= 12√2 - 10√2 + 32√2 - 60√2

= 12√2 + 32√2 - 10√2 - 60√2

= 44√2 - 70√2

= -26√2

= -26 × 1.414

= -36.764

Answered by Bhavyanayak
0

Your answer is 138.572

step by step explanation:

We know that ;

 \sqrt{2}  = 1.414

(1)

3 \sqrt{32} = 3 \times  \sqrt{2}  \times  \sqrt{16}

 = 3 \times 4 \times  \sqrt{2}

 = 12 \sqrt{2}

(2)

2 \sqrt{50}  = 2 \times  \sqrt{2}  \times  \sqrt{25}

 = 2 \times  \sqrt{2}  \times 5

 = 10 \sqrt{2}

(3)

4 \sqrt{128}  = 4 \times  \sqrt{2}  \times  \sqrt{64}

 = 4 \times  \sqrt{2}  \times 8

 = 16 \sqrt{2}

(4)

20 \sqrt{18}  = 20 \times  \sqrt{2}  \times  \sqrt{9}

 = 20 \times 3 \times  \sqrt{2}

 = 60 \sqrt{2}

Question :

3 \sqrt{32}  - 2 \sqrt{50}  + 4 \sqrt{128}  - 20 \sqrt{18}

Plugging the values :

 = 12 \sqrt{2}  + 10 \sqrt{2}  + 16 \sqrt{2}  + 60 \sqrt{2}

As we mentioned above ;

 \sqrt{2}  = 1.414

Substitute the value of Root 2 :

 = 12 \times 1.414 + 10 \times 1.414 + 16 \times 1.414 + 60 \times 1.414

 = 138.572

So your answer is 138.572

Hope it is clear :-)

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