Question

Please help fast very urgent i will mark you brainliest​

Answer 1

Answer:

let 1/(3x+2y) = a and 1/(3x-2y) = b

so, given equations becomes,

a - b = 1/8

i.e 8a - 8b = 1.......(1)

3a - b = 1/2

i.e 6a -2b = 1........(2)

multiply equation 2 by 4 , we get

24a - 8b = 4 .......(3)

subtracting equation 1 from 3, we get

24a-8b-8a+8b = 4 -1

16a = 3

so, a = 3/16

put a = 3/16 in equation (1), we get

8(3/16)-8b = 1

-8b = 1-3/2

-8b = -1/2

b = 1/16

but, a = 1/(3x+2y). and b = 1/(3x-2y)

3/16 = 1/(3x+2y). and 1/16 = 1/(3x-2y)

3x + 2y = 16/3..... (3) and 3x - 2y = 15....(4)

adding equation 3 and 4, we get

6x = 16/3+ 15= 61/3

x= 61/18.......answer of x

put x = 61/18 in equation 4, we get

3(61/18) - 2y = 15

-2y = 15 - 61/6 = 29/6

y = -29/12...... answer of y