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Class-9
Science
Chapter-8
Answers
Answer:
Here we have, Diameter = 200 m, therefore, radius = 200m/2 = 100 m
Time of one rotation = 40s
Time after 2m20s = 2 x 60s + 20s = 140s
Distance after 140 s = ?
Displacement after 140s =?
We know that, velocity along a circular path
=
Circumference
time
⇒
v
=
2
π
r
40
s
⇒
v
=
2
×
3.14
×
100
m
40
s
⇒
v
=
628
m
40
s
⇒
v
=
15.7
m
/
s
(a) Distance after 140s
We know that,distance=velocity ×time
⇒ distance=15.7m/s ×140 s = 2198 m
(b) Displacement after 2 m 20 s i.e. in 140 s
Since,rotatin in 40 s=1
Therefore, rotation in
1
s
=
1
40
∴ rotation in
140
s
=
1
40
×
140
=
3.5
Therefore, in 3.5 rotations athlete will be just at the opposite side of the circular track, i.e. at a distance equal to the diameter of the circular track which is equal to 200 m.
Therefore, Distance covered in 2 m 20 s = 2198 m
And, displacement after 2 m 20 s = 200m
Answer:
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