Question

please help! find length of DE!

Answer 1

Given:-

• angleD = 60

• EF = 4√3

To find:-

• DE = ?

Solution:-

As we know that,

As we know that

$\tan( \alpha ) = \frac{perpendicular}{base}$

$\tan(60) = \sqrt{3}$

So,

$= > \tan(60) = \frac{4 \sqrt{3} }{x} \\ = > \sqrt{3} = \frac{4 \sqrt{3} }{x } \\ = > x = \frac{4 \sqrt{3} }{ \sqrt{3} } \\ = > x = 4$

Hence the value of DE = 4

Hope its help uh❤

Answer 2

$\huge\underline\bold{AnSwEr,}$

Given:-

• angleD = 60

• EF = 4√3

To find:-

• DE = ?

Solution:-

As we know that,

As we know that

$\tan( \alpha ) = \frac{perpendicular}{base}$

$\tan(60) = \sqrt{3}$

So,

$= > \tan(60) = \frac{4 \sqrt{3} }{x} \\ = > \sqrt{3} = \frac{4 \sqrt{3} }{x } \\ = > x = \frac{4 \sqrt{3} }{ \sqrt{3} } \\ = > x = 4$

Hence the value of DE = 4

#MasterHunteR_@±{=°=}