Question

PLEASE HELP!!!
Find the root of this equation:
(0.3x^2-0.3x)(5x^3-0.2x^2)=0

Answer 1

"0.2" was replaced by "(2/10)". 2 more similar replacement

$( \frac{3}{10} ) \times x-( \frac{2}{10} ) \times x^2-(-2)=0 \\after \: simpifying \\ 3x - 2x {}^{2} =   -x  \times (2x - 3)  \\ finding \: factors \\ \\ </p><h3>-40   +   1   =   -39   \\-20   +   2   =   -18 \\-10   +   4   =   -6   \\-8   +   5   =   -3   \\    -5   +   8   =   3   \\ \\ - 2x {}^{2}  - 5x + 8x + 20 \\ (-x+4)   \times   (2x+5)$

The product of several terms equals zero.

When a product of two or more terms equals zero, then at least one of the terms must be zero.

We shall now solve each term = 0 separately In other words, we are going to solve as many equations as there are terms in the product .Any solution of term = 0 solves product = 0 as well.

Answer 2

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x = 2 and y = 3

Step-by-step explanation:

Given :0.2x+0.3y=1.30.2x+0.3y=1.3

0.4x+ 0.5y=2.30.4x+0.5y=2.3

To Find : solve using substitution method

Solution :

0.2x+0.3y=1.30.2x+0.3y=1.3 -----1

0.4x+ 0.5y=2.30.4x+0.5y=2.3 ------2

Substitute the value of x from 1 in 2

2.30.4(0.2/1.3−0.3y)+0.5y=2.3

y=3y=3

0.2x+0.3(3)=1.30.2x+0.3(3)=1.3

0.2x=1.3-0.90.2x=1.3−0.9

0.2/1.3−0.9

x=2x=2

So, x = 2 and y = 3