Question

please help for question 99

Answer 1

present volume of water = πr^2h
volume of sphere= 4/3πR^3
now total volume after submerging =
= 4/3πR^3+πr^2h = π5472
than it is also equal to πr^2H ( H= present hight) =
so πr^2H=π5472
= H = 5472/r^2
= 5472/225
= 24.32
so raised hight = H-h= 24.32-20 cm
=4.32cm

Answer 2

plz mark as brainliest plz..