Question

please help for this question​ I'll mark as brilliant

Answer 1

Answer:

Question:-

(1) Evaluate if a = 3, b = 0 , c = -2

i) ab + 2bc + 3ca + 4abc

ii) a³ + b³ + c³ - 3abc

Solution :-

i) ab + 2bc + 3ca + 4abc

Putting their values, we get:-

=> a = 3

=> b = 0

=> c = -2

So, Equation will be,

=> 3×0 + 2×0×3 + 3×(-2)×3 + 4×3×0×(-2)

=> 0 + 0 + -18 + 0

=> -18

ii) a³ + b³ + c³ - 3abc

By putting their values we get :

=> a = 3

=> b = 0

=> c = -2

In, Equation :-

=> (3)³ + (0)³ + (-2)³ - 3×3×0×(-2)

=> 27 + 0 + (-8) - 0

=> 27 - 8

=> 19

Therefore, Answers are:-

• i) -18
• ii) 19

Answer 2

$\huge\colorbox{white}{ \colorbox{white}{\colorbox{white}{Question}}}$

If ,

• a = 3
• b = 0
• c = -2

Then Evaluate ,

(1) ab + 2bc + 3ca + 4 abc

(2) a³ + b³ + c³ - 3abc

$\bold\color{red} {Solution}$

________________________________

(1) ab + 2bc + 3ca + 4 abc

$\color{green} {By\: substituting\:values}$

$\Huge\sf\implies$ $\tt \:(3) (0) + 2 (0) (-2) + 3 (-2) (3) + 4 (3) (0) (-2)$

$\color{green}{After\:Calculation\:We\:will\:get}$

$\Huge\sf\implies$ $\tt \: 0 + 0 + (-4) + (-2)$

$\Huge\sf\implies$ -7

Therefore , Ans is -7

________________________________

(2) a³ + b³ + c³ - 3abc

$\color{green} {By\: substituting\:values}$

$\Huge\sf\implies$ $\tt \: (3)³ + (0)³ + (-2)³ - 3 × 3 × (0) × (-2)$

$\color{green}{After\:Calculation\:We\:will\:get}$

$\Huge\sf\implies$ $\tt \: 27 + 0 - 8 - 0$

$\Huge\sf\implies$$\tt \: 19$

Hence , required value is 19

_______________________________