Question

please help friends​

Answer 1

Heya

Before doing its integration let's make this function simpler.

1/ { 1 - Sin x/2 }

MULTIPLY NR and DN by 1 + Sinx/2

=

{ 1 + Sinx/2 }

____________

Cos² x/2

=>

Sec² x/2 + (Tan x/2 ) × (Sec x/2 )

=>

So, integration of 1/ { 1 - Sin x/2 } =

integration of Sec² x/2 + (Tan x/2 )× (Secx/2)

=>

2 Tan x/2 + 2 Sec x/ 2 + c

Where c is called constant of integration.