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Heya
Before doing its integration let's make this function simpler.
1/ { 1 - Sin x/2 }
MULTIPLY NR and DN by 1 + Sinx/2
=
{ 1 + Sinx/2 }
____________
Cos² x/2
=>
Sec² x/2 + (Tan x/2 ) × (Sec x/2 )
=>
So, integration of 1/ { 1 - Sin x/2 } =
integration of Sec² x/2 + (Tan x/2 )× (Secx/2)
=>
2 Tan x/2 + 2 Sec x/ 2 + c
Where c is called constant of integration.
Before doing its integration let's make this function simpler.
1/ { 1 - Sin x/2 }
MULTIPLY NR and DN by 1 + Sinx/2
=
{ 1 + Sinx/2 }
____________
Cos² x/2
=>
Sec² x/2 + (Tan x/2 ) × (Sec x/2 )
=>
So, integration of 1/ { 1 - Sin x/2 } =
integration of Sec² x/2 + (Tan x/2 )× (Secx/2)
=>
2 Tan x/2 + 2 Sec x/ 2 + c
Where c is called constant of integration.
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