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AB and CD are two parallel chords of a circle of radius 5cm. If the chords are on the opposite sides of the centre and the distance between them is 7cm. Find the length of the chords.
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Answer:
AB=8cm
⇒AE=4cm
CD=6m⇒CF=3cm
In△AED
AE=4cm,AO=5cm
OE=
(AO)
2
−(AE)
2
=
5
2
−4
2
=3cm
In△OFC
CF=3cm,CO=5cm
OF=
OC
2
−CF
2
=
5
2
−3
2
=4cm
∴ Distance between the chords=4cm−3cm=1cm
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