.please help frnds?........
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2x2-x-3
2x2-2x-3x-3=0
2x(x-1)-3(x-1)=0
x=1. x=3/2
2x2-2x-3x-3=0
2x(x-1)-3(x-1)=0
x=1. x=3/2
pokemanticash:
wrong answer
??
(2x-3) (x+1) ans
factorise it see question
yeah...but if we need to find x then what i have written would be correct
Answered by
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Given Equation is 2x^2 - x - 3
It can be written as
= > 2x^2 + 2x - 3x - 3
= > 2x(x + 1) - 3(x + 1)
= > (2x - 3)(x + 1).
Therefore, factorization of 2x^2 - x - 3 = (2x - 3)(x + 1).
Hope this helps!
:-)
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