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How many millimeters of a 1.75 M LiCl solution contain 15.2g of LiCl?
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Moles of LiCl in 15.8 g
15.8/42.39 g/mol = 0.373 mol
molarity = moles/in a L
volume that gas 0.373 moles is = x
(1.74/1000 mL)*x = 0.373 mol
solve for x
x= 214.37 mL
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