Question

Please help how to solve​

Answer 1

Answer:

In figure, AD is a median of AABC. Prove that AB [Hint. Produce AD to E such that AD = DE and

+ AC > 2AD.

join C and E.]

OR

Prove that the sum of any two sides of a triangle is greater than twice the length of median drawn to the third side.

Construction: Produce AD to E such that AD =

DE and join C and E.

Proof.: In AADB and AEDC,

AD = DE By const.

BD = DC

1. AD is a median of AABC ZADB = LEDC

| Vertically Opposite Angles

. AADB = AEDC | SAS Axiom

: AB = EC (1) C.P.C.T.

In AAEC,

AC + EC > AE

The sum of any two sides of a triangle is greater than the third side

AC + AB > AE

AB + AC > AE

- AB + AC > 2AD.

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X) Switch

| From (1)

| By const.

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