Math, asked by allisquier, 1 year ago

PLEASE HELP! I HAVE A MATH TEACHER THAT DOESN'T TEACH US ANYTHING AND WE HAVE A QUIZ COMING UP.
Simplify the expression. Assume all variables are positive.
$\frac{\sqrt[3]{64x^3y} }{4x^3y}$
Note: On the bottom part of the fraction, the $x^{3}$ is a negative x to the third

allisquier: lol, feel like i am going to fail algebra 2, plus, so many parents have complained, but the principle thinks she is a great teacher, WTF!

allisquier: lol

allisquier: and a lot of last years class hated her class too, i mean, she seems like she would be a nice person, but is a horrible teacher

allisquier: lol

allisquier: thanks

Answers

Answered by SnehaG

hii...

here is ur answer.. ^↓^

(3√64x³y)/4x³y
3(4x³y)/4x³y

3/1

hence

answer is ^↓^

" "3" "

allisquier: is this putting in the fact that the x to the third in the denominator is a negative three, so the exponent is negative?

yuvrajkj: if x is negative, then any even power of x will make it positive

yuvrajkj: any odd power will keep it negative

allisquier: the x isn't negative, the exponent itself is negative

yuvrajkj: x to the power -3??

allisquier: yeah

allisquier: and it is a cube root, not times 3

allisquier: Hey, can you fix the problem, or i will clear it so i can get a right answer to help me

Answered by sheoranprateek

according to question
3×√64x^3/4x^3
3×4x^3/4x^3
3×1
3 is ur right answer

pranavrai: wrong..thats a cube root not 3 i guess

allisquier: yeah, it is a cube root

sheoranprateek: is my question right

allisquier: Hey, can you fix the problem, so that i know what the right answer is, or i have to clear it

pranavrai: answer will be 1/y^(2/3).x^2

pranavrai: just started using the app so dont know how to answer..

allisquier: To sheoranprateek, no your answer isn't right, it is a cube root, not times 3

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