Question

please help I'll follow please urgently​

Answer 1

Answer:

$1) \\ \\ \\ {( \sin( \alpha ) + \cos( \alpha )) }^{2} - {( \sin( \alpha ) - \cos( \alpha )) }^{2} = 4 \sin( \alpha ) \cos( \alpha ) .$

$2) \\ \\ \\ \\ \frac{ { \sin( \alpha ) }^{4} - { \cos( \alpha ) }^{4} }{ { \sin( \alpha ) }^{2} - { \cos( \alpha ) }^{2} } = 1.$

Step-by-step explanation:

$1) \\ \\ \\ {( \sin( \alpha + \cos( \alpha ) ) }^{2} - {( \sin( \alpha ) - \cos( \alpha )) }^{2} \\ = { \sin( \alpha ) }^{2} + { \cos( \alpha ) }^{2} + 2 \sin( \alpha ) \cos( \alpha ) - { \sin( \alpha ) }^{2} - { \cos( \alpha ) }^{2} + 2 \sin( \alpha ) \cos( \alpha ) \\ \\ = 4 \sin( \alpha ) \cos( \alpha ) \\ \\ = rhs$

$2) \\ \\ \\ \\ \\ \frac{ { \sin( \alpha ) }^{4} - { \cos( \alpha ) }^{4} }{ { \sin( \alpha ) }^{2} - { \cos( \alpha ) }^{2} } = \frac{{( \sin( \alpha ) }^{2} + { \cos( \alpha ) }^{2} )( { \sin( \alpha ) }^{2} - { \cos( \alpha ) }^{2} )}{ {( \sin( \alpha ) }^{2} - { \cos( \alpha ) }^{2}) } \\ \\ = { \sin( \alpha ) }^{2} + { \cos( \alpha ) }^{2} \\ \\ = 1 \\ \\ = rhs.$