Question

Please help.....
If sinA=3/5,find the value of (tanA+secA)^2.​

Answer 1

Answer:

(tanA+secA)²=4

Step-by-step explanation:

sinA=3/5- - -1

sinA=perpendicular/hypotenuse-- -2

on comparing 1&2 we get

perpendicular=3

hypotenuse=5

usin Pythagoras theorem we get

base= 4

tanA=perpendicular/base

=3/4

secA=hypotenuse/base

=5/4

(tanA+secA)²=[(3/4)+(5/4)]²

=(8/4)²

=2²

=4