please help!!!!!
if the length of a rectangle is increased by 7 m and the breadth is decreased by 3 m its area remain unchanged similarly if the length is decreased by 7 m and the breadth is increased by 5 m, still area remains unchanged. Find the length and the breadth of the rectangle
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Let :
- Initial length = x
- Initial breadth = y
- Area of rectangle = xy
Given :
- Length is increased by 7 m and the breadth is decreased by 3 m its area remain unchanged
- length is decreased by 7 m and the breadth is increased by 5 m, still area remains unchanged.
Formula used :
- Area of rectangle = length×breadth
Solution :
First case,
=> (x+7)(y-3) = A = xy
=> xy -3x + 7y - 21 = xy
=> 7y - 3x - 21 = xy-xy
=> 7y - 3x - 21 = 0 ........... equation 1
Second case,
=> (x-7)(y+5) = A = xy
=> xy + 5x - 7y -35 = xy
=> 5x - 7y - 35 = xy - xy
=> 5x - 7y - 35 = 0 ........... equation 2
On Adding equation 1 & 2 , we get
=> (7y - 3x - 21 ) + ( 5x - 7y - 35) = 0+0
=> 7y - 7y + (5x - 3x) - (21+35) = 0
=> 2x - 56 = 0
=> 2x = 56
=> x = 56/2
=> x = 28
Putting value of x, in equation 1 [ 7y - 3x - 21 = 0] we get;
=> 7y - 3(28) - 21 = 0
=> 7y = 21 + 84
=> 7y = 105
=> y = 105/7
=> y = 15
ANSWER :
- Length = x = 28m
- Breadth = y = 15cm
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