Question

please help if you can
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Answer 1

see this pc you're answer

thank you

Answer 2

Answer:

We have the quadratic equation in x, x^2 + mx + m^2 + a = 0, and its given that it has roots p and q.

So,

sum of roots = p + q = -m/1 = -m

product of roots = pq = m^2 + a

We have to find the value of p^2 + q^2 + pq

p^2 + q^2 + pq

= (p + q)^2 - pq

Now, we'll use the values of (p + q) and pq we calculated above;

= (-m)^2 - (m^2 + a)

= m^2 - m^2 - a

= -a

Hence, the value of p^2 + q^2 + pq is -a