Question

please help if you know
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Answer 1

Given: V=12V, Resistance of A=4Ω, Resistance of B=6Ω, Internal battery resistance =2Ω

(i) Total Resistance =4+6+2=12Ω

I (current in circuit)=Totalresistancee.m.f.=1212=1amp

(ii) Voltage drop Ir=1×2=2volt

Terminal Voltage = emf - Voltage drop

                             =12−2=10 volts

(iii) Potential difference across 6Ω=IR

                                                          =1×6=6V

(iv) Energy spent =I2Rt

                             =(1)2×4×60=240J

Answer:

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