Question

please help !


(ii) and (iii)

Answer 1

1):- SO3 - O2 - w g

n ( SO3 ) = w/80

n (O2 ) - w/32

The partial pressure will be in the ratio of their moles.

So

P ( SO3 ) : P (O2) = w/80 : w/32

1/80 : 1/32 = 1/5 :1/2 = 2:5 Ans

so correct option is (b)
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Sorry

i am not given u second solution .

i will try to sometime later

Answer 2

Hey there !!!!!

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Ratio of masses of SO₃ and O₂ confined in a vessel is 1:1

Partial Pressure (SO₃) : Partial Pressure (O₂) = ?

  = w/Molar mass(SO₃) : w/ Molar mass (O₂)

  =w/80:w/32

  = 32:80
  =2:5

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Let density of gas (A)= dₐ 

density of gas(B)=dₓ

According to question 

density of gas A is twice that of gas B at same temperature


  dₐ=2dₓ

And

Molecular mass of B (mₓ)=3(molecular mass of A (mₐ)

    mₓ=3mₐ 

Ideal gas equation :    PV=nRT


                                    PV=w*R*T/molecular mass


                                   P*molecular mass=w*R*T/V

   But density=weight/volume=w/V

                                 P*M=dRT

Now,

Pressure of gas A=Pₐ  Molecular mass=mₐ  density=dₐ Temperature=t

Pressure of gas B=Pₓ  Molecular mass=mₓ  density=dₓ  Temperature=t


                   Pₐ*mₐ=dₐ*R*t---Equation 1


                  Pₓ*mₓ=dₓ*R*t----Equation 2

Dividing equation 1 and 2


                 Pₐ*mₐ/Pₓ*mₓ = dₐ/dₓ

But,  dₐ=2dₓ                mₓ=3mₐ

  ⇒⇒dₐ/dₓ=2         ⇒⇒mₓ/mₐ=3

                
          Pₐ*mₐ/Pₓ*mₓ = dₐ/dₓ


         Pₐ/Pₓ = dₐ*mₓ/mₐ*dₓ= 3*2


         Pₐ:Pₓ=6:1


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Hope this helped you..................