Math, asked by ArmouredBobcat, 8 months ago

please help, ill mark it as brainliest. 3^m^+^4-6*3^m^+^2/7*2^m^+^2

Answers

Answered by sreelekha1022
1

Answer:

) x + 3 = 0

LHS = x + 3

Put x = 3, we get

LHS = 3 + 3 = 6 ≠ RHS

So, the equation is not satisfied.

(ii) x + 3 = 0

LHS = x + 3

Put x = 0, we get

LHS = 0 + 3 = 3 ≠ RHS

So, the equation is not satisfied.

(iii) x + 3 = 0

LHS = x + 3

Put x = -3, we get

LHS = -3 + 3 = 0 = RHS

So, the equation is satisfied.

(iv) x - 7 = 1

LHS = x - 7

Put x = 7, we get

LHS = 7 - 7 = 0 ≠ RHS

So, the equation is not satisfied.

(v) x - 7 = 1

LHS = x - 7

Put x = 8, we get

LHS = 8 - 7 = 1 = RHS

So, the equation is satisfied

Answered by Anonymous
43

 {\boxed{\bold{ \green{verified \: answer}}}}

 \huge\bold{answer}

 \bold{x + 3 = 0}

  \bold{lhs = x + 3}

 \bold{put \: x \:  = 3 \:  \:  \: we \: \:  get}

 \bold{lhs = 3 + 3 = 6 \: lhs}

 \bold{so, the \:  \: equation \:  \: is \:  \: not \:  \: satisfied}

 \boxed{\green{okk..hope \:  \:  u \: \:  \:  \:  understand}}

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