please help☺☺ in doing both questions
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see in 1 question take sin theta is equal to 3/5 and draw a triangle and by using pythogarus find value of third side.Then find value of cos theta and square the value...and in second question put the value of sin60,cos60 and sin 30....please mark as brainliest friend
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sin theta= 3/5
as we know sin² theta + cos² theta
or, cos² theta=1-(3/5)²
= 1-9/25
=16/25
therefore, cos² theta= (4/5)²
next one, sin60°.cos30° -cos60°-sin30°
= √3/2.√3/2-1/2.√3/2
= 1
as we know sin² theta + cos² theta
or, cos² theta=1-(3/5)²
= 1-9/25
=16/25
therefore, cos² theta= (4/5)²
next one, sin60°.cos30° -cos60°-sin30°
= √3/2.√3/2-1/2.√3/2
= 1
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par answer to mera correct hai
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