Math, asked by Anonymous, 11 months ago

please help in following question

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Answered by IamIronMan0
0

Answer:

2

Step-by-step explanation:

your expression is equal to

 {x}^{2}  +  {y}^{2}  +  {z}^{2}   - yz - zx \\  = \frac{1}{2} ( { (x - y)}^{2}  +  { (y - z) }^{2}   + {(z - x)}^{2} ) \\  = 0

Which is only true if x = y = z

so

 \frac{x + y}{z}  =  \frac{x + x}{x} = 2

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