Question

please help in question 13 and 14 please it's urgent

Answer 1

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Q.12) 1485-3=1482.........(as the remainder leaves 3)
          940-4=936...........(as the remainder leaves 4)

finding the hcf of the nos
                 1482=936*1+546
                 936=546*1+390
                 546=390*1+15
                 390=156*2+78
                 156=78*2+0

hence the hcf is 78 or the largest no that divides 1482 &936

Q13) will be repeating the same steps as done in the above question
        129-1=128........(remainder is 1)
         226-2=224.............(remainder is 2)
         323-3=320........(remainder is 3)

hcf of 320 and 224 are 
         320=224*1+96
         224=96*2+32
         96=32*3+0
hcf of 2 nos is 32

hcf of 32 and 224
        224=32*4+0

hence the largest no which divides the 3 nos is 32

(*)sign of multiplication

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