Question

please help in question no. 9​

Answer 1

By data,

On passing current of 0.5 ampere in a resistor, potential difference of 2.5 volt produces across resistor.

• Current, I = 0.5 A

• Potential difference, V = 2.5 volt.

According to ohms law,

The current flowing through the conductor is directly proportional to the potential difference across the two ends of the conductor.

V = IR

Where R is the resistance of the resistor.

$V = IR \\ \\ 2.5 = 0.5 \times R \\ \\ R = \dfrac{2.5}{0.5} \\ \\ R = \dfrac{2.5}{0.5} \times \dfrac{10}{10} \\ \\ R = \dfrac{2.5 \times 10}{0.5 \times 10} \\ \\ R = \frac{25}{5} \\ \\ R = 5 \: ohm$

The resistance of the resistor is 5 ohm.

Again by data,

New potential difference, V = 1 volt.

Resistance, R = 5 ohm.

New current be I.

V= IR

$1 = I \times 5 \\ \\ I = \frac{1}{5} \\ \\ I = 0.2 \: ampere$

The new current through resistor is 0.2 A.

Answer 2

Answer:

potential difference is directly proportional to current

0.5A = 2.5V

X=1.0V

we can do cross multiplication

2.5×X = 0.5×1

X=0.5×1/2.5

X=0.2

current flow through resister is 0.2A