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Answer:
ΔXOY ≅ ΔXOZ (SAS)
Step-by-step explanation:
Given,
XY = XZ ; YO = ZO
Therefore,
∠Y = ∠Z ( Angles opposite to equal sides of a triangle are equal )
Therefore,
In ΔXOY & ΔXOZ
⇒ ∠Y = ∠Z
⇒ XY = XZ
⇒ YO = ZO
Therefore,
ΔXOY ≅ ΔXOZ (SAS)
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