Question

please help in this question​

Answer 1

Answer:

90

Step-by-step explanation:

Angle EAB + Angle RBA = 180° (AB being transversal on the parallel lines DE & QR)

Now, since both these angles are bisected by AP and BP respectively, Angle EAP + Angle RBP = 90°

And we know that :

Angle EAP + Angle RBP + Angle APB = 180° {Triangle Property }

Angle APB = 180-90 = 90°

Answer 2

Answer:

an.APB = 90°

Step-by-step explanation:

Given:- DE||QR, AP and BP are bisectors of an.EAB and an.RBA

To find:- an.APB

Proof:-

When know that DE||QR then AB is a transversal

Thus, an.EAB + an.RBA = 180° (Sum of Alternate Interior Angles)

Let's say an.EAB = x and an.RBA = y

then x + y = 180-----1

also, an.PAB = x/2 and an.PBA = y/2

Thus, by Angle Sum Property

an.PAB + an.PBA + an.APB = 180°

x/2 + y/2 + an.APB = 180°

(x + y)/2 + an.APB = 180°

an.APB = 180 - (x + y)/2

From eq.1 we get

an.APB = 180 - (180)/2 = 180 - 90

Therefore,

an.APB = 90°

Hope you understood it........All the best