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it is parallel combination
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V = 3V, R1 = 10Ω, R2 = 15Ω
a) resistors are in parallel combination.
b) as I = V/R, therefore:
I1 = V/R1 and I2 = V/R2 (as V remains constant in parallel combination)
therefore,
I1 = 3/10 = 0.3A
I2 = 3/15 = 1/5 = 0.2A
therefore 0.3A flowing through R1 and 0.2A flowing through R2
c) 1/Rp = 1/R1 + 1/R2
= 1/10 + 1/15
= (2+3)/30
= 5/30
therefore Rp = 30/5 = 6Ω
I = V/R
therefore I = 3/6 = 0.5A
so reading in ammeter is 0.5A
a) resistors are in parallel combination.
b) as I = V/R, therefore:
I1 = V/R1 and I2 = V/R2 (as V remains constant in parallel combination)
therefore,
I1 = 3/10 = 0.3A
I2 = 3/15 = 1/5 = 0.2A
therefore 0.3A flowing through R1 and 0.2A flowing through R2
c) 1/Rp = 1/R1 + 1/R2
= 1/10 + 1/15
= (2+3)/30
= 5/30
therefore Rp = 30/5 = 6Ω
I = V/R
therefore I = 3/6 = 0.5A
so reading in ammeter is 0.5A
serdan2114:
Thanxx
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