Please help in this question
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Answered by
0
heyy !!
your answer⬇⬇
3)origin=(0,0)
now , distance=√(x^2+y^2)
4)d=-4
a7=4
a+(7-1)×-4=4
a=28
5)(cos^2 67°-sin^2 23°)
=cos^2(90°-23°)-sin^2 23°
=sin^2 23°-sin^2 23°=>0
hope it help. :)
your answer⬇⬇
3)origin=(0,0)
now , distance=√(x^2+y^2)
4)d=-4
a7=4
a+(7-1)×-4=4
a=28
5)(cos^2 67°-sin^2 23°)
=cos^2(90°-23°)-sin^2 23°
=sin^2 23°-sin^2 23°=>0
hope it help. :)
Answered by
2
3-
By Distance Formula,

d =
distance =
4)-

4 = a + [6*(-4)]
4 =a + [-24]
4 = a- 24
4+24= a
28 = a
first term is a i.e. 28
5)-
[tex]cos^{2} 67 - sin^{2} 23 [/tex]

[tex]cos^{2} 67 - cos^{2} 67 [/tex]
= 0
i hope this will help you
-by ABHAY
By Distance Formula,
d =
distance =
4)-
4 = a + [6*(-4)]
4 =a + [-24]
4 = a- 24
4+24= a
28 = a
first term is a i.e. 28
5)-
[tex]cos^{2} 67 - sin^{2} 23 [/tex]
[tex]cos^{2} 67 - cos^{2} 67 [/tex]
= 0
i hope this will help you
-by ABHAY
abhi569:
thanks for marking as brainlist
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