Question

please help in this question​

Answer 1

Knowledge required:

↪️ A v-t graph parallel to x axis, represents, uniform motion of a body that have a constant speed.

↪️ Speed and velocity are same in the matter of graphs in motion.

↪️ The slope of V-T graph gives the _____ of the object in motion.

• The slope of Velocity Time graph give the acceleration of the object in motion.

↪️ The area under curve of V-T graph gives the _____ of the object in motion.

• The area under curve of Velocity Time graph gives the distance/displacement of the object in motion.

Required solution:

Find the distance travelled from B to C!

$:\implies \sf s \: = Area \: under \: curve \\ \\ :\implies \sf Distance \: = Area \: under \: curve \\ \\ :\implies \sf Distance \: = Area \: of \: rectangle \\ \\ :\implies \sf Distance \: = Length \times Breadth \\ \\ :\implies \sf Distance \: = (40-0) \times (6-3) \\ \\ :\implies \sf Distance \: = 40 \times 3 \\ \\ :\implies \sf Distance \: = 120 \: km$

Find the acceleration from A to B!

$:\implies \sf Acceleration \: = \dfrac{Change \: in \: velocity}{Time} \\ \\ :\implies \sf a \: = \dfrac{v-u}{t} \\ \\ :\implies \sf a \: = \dfrac{40-20}{(3-0)} \\ \\ :\implies \sf a \: = \dfrac{20}{3} \\ \\ :\implies \sf a \: = 6.66 \: ms^{-2} \\ \\ :\implies \sf Acceleration \: = 6.66 \: ms^{-2}$

What type of acceleration is shown from C to D?

From section C to D the acceleration is negative acceleration shown.