Please help. It is urgent...pleaseQUESTION NUMBER 11...
And it is a humble request that I want an original answer, please please. ...urgent
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mysticd:
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given equation 3x+ky=5 ----(1) this shows a line on the graph
i) if (1) passing through the point (-1,2) then
substitute x=-1, y=2 in (1)
3*(-1) + k(2) =5
⇒-3 +2k= 5
⇒2k= 5+3
⇒2k= 8
∴k= 8/2 =4
ii) if the line passes through the point (1,0)
put x= 1 and y=0 in (1)
3*1 +k*0 =5
3=5 [false]
therefore for any value of k ,
the line doesnot passes through the point (1,0)
i) if (1) passing through the point (-1,2) then
substitute x=-1, y=2 in (1)
3*(-1) + k(2) =5
⇒-3 +2k= 5
⇒2k= 5+3
⇒2k= 8
∴k= 8/2 =4
ii) if the line passes through the point (1,0)
put x= 1 and y=0 in (1)
3*1 +k*0 =5
3=5 [false]
therefore for any value of k ,
the line doesnot passes through the point (1,0)
Thank you so much Mysticd.
u'r welcome
Sorry to ask Mysticd, but are you sure?
thank you selecting as brainliest
my pleasure,helped a lot....
keep answering please...
sure
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