Question

please help, it's of comparing quantity chapter​

Answer 1

★Answer :-

$\rm{The \: sum \: or \: principal\: is \: rs. \: \bf 40000} \bigstar$

★Step-by-step-Explaination :-

★Given :-

• $\rm \: Time \ = 2 \: years$
• $\rm \: Rate \: of \: interest \ = 5 \%$
• $\rm \: Simple \: Interest \ = 4000$

★Find :-

• Principal or Sum = ?

★Let :-

• Let the Principal be P .
• Let the Simple Interest be S.I.
• Let the Rate of Interest be R .
• Let the Time be T .

★ Solution :-

Hᴇɴᴄᴇ , We know that

$\rm \: Simple \: Interest = \dfrac{Principal \times \: Rate \: of \: interest \times \: Time}{100}$

So ,

According to the formula put the values :-

$\rm \: \implies 4000= \dfrac{P \times \: 5 \times \: 2}{100}$

Now , Principal (P) will come to L.H.S of equals to . And , 400 will be multiplied with 100 ,

$\rm \: \implies P= \dfrac{4000 \times 100}{5 \times 2}$

Now , it will be divided ,

$\rm \: \implies P= 4000 \times 10$

On being multiplied ,

$\rm \: \implies \bf \: P= 40000$

Hᴇɴᴄᴇ , Principal is Rs.40000 .

★Additional Information :-

$\boxed{\sf1.)Simple \;Interest =\dfrac{P\times R\times T}{100}}$

$\boxed{\sf2.)Principal =\dfrac{ R\times T}{100\times S.I}}$

$\boxed{\sf3.) Rate\;Of\;Interest=\dfrac{P\times T}{100\times S.I}}$

$\boxed{\sf4.)Time =\dfrac{P\times R}{100\times S.I}}$

$\sf 5.) Amount = Principal \;+\;Simple\; Interest$

▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬▬