please help it's urgent.
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[Note : refer the attachment]
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▶ in the question , As we have given the value of a, put the value of a in LHS [2a^3 +6a]
▶Apply the identity ( a - b) ^3
▶multiply 2 inside the bracket after the expansion of term using formula ( a - b) ^3
▶Then cancel out the like terms which have opposite signs
▶ finally remains 4 - 1
▶ 4 - 1 = 3 , hence RHS
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★ identity used :
( a - b) ^3
= a^3 - 3a^2b + 3ab^2 - b^3
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