Question

Please help it's urgent ​

Answer 1

first u add all the terms in question

u get

( a(b+c)^2+b(c+a)^2+c(a+b)^2)/abc

(b^2(a+c)+c^2(a+b)+a^2(c+b)+6abc)/abc

• hence it is given that a+b+c=0
• then a+c=-b
• a+b=-c
• b+c=-a

then after substituting this values in above equation we get

(-(b^3+a^3+c^3)+6abc )/abc

and also it is given that (a^3+b^3+c^3)=3abc

using this we get

(-3abc+6abc)/abc=3abc/abc=3

hence proved