Question

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Answer 1

Answer:

$( \frac{ \tan(60) + 1}{ \tan(60) - 1 } ){}^{2} = \frac{1 + \cos(30) }{1 - \cos(30) } \\ \\ \\ \tan(60) = \sqrt{3} \: \: and \: \: \cos(30) = \frac{ \sqrt{3} }{2} \\ \\ put \: the \: value \: in \: above \: equation \\ (\frac{\sqrt{3} + 1}{ \sqrt{3} - 1} ) {}^{2} = \frac{1 + \frac{ \sqrt{3} }{2} }{1 - \frac{ \sqrt{3} }{2} } \\ \frac{( { \sqrt{3}) }^{2} + 1 + 2 \sqrt{3} }{( \sqrt{3} {)}^{2} + 1 - 2 \sqrt{3} } = \frac{ \frac{2 + \sqrt{3} }{2} }{ \frac{2 - \sqrt{3} }{2} } \\ \frac{3 + 1 + 2 \sqrt{3} }{3 + 1 - 2 \sqrt{3} } = \frac{2 + \sqrt{3} }{2} \times \frac{2}{2 - \sqrt{3} } \\ \frac{4 + 2 \sqrt{3} }{4 - 2 \sqrt{3} } = \frac{2 + \sqrt{3} }{2 - \sqrt{3} } \\ \frac{2(2 + \sqrt{3}) }{2(2 - \sqrt{3}) } = \frac{2 + \sqrt{3} }{2 - \sqrt{3} } \\ \frac{2 + \sqrt{3} }{2 - \sqrt{3} } = \frac{2 + \sqrt{3} }{2 - \sqrt{3} }$

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Answer 2

Answer:

Chrome

Step-by-step explanation:

1.open chrome browser

2.search it up

3. S T O N K S.