Question

please help
it's very urgent
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Answer 1

Step-by-step explanation:

In ∆ PDC and ∆ PAB PD = PB (data) ∠DPC = ∠APB [V.O.A] ∠PD∆ = ∠PBA [Alternate angles AB|| CD] ∴ ∆ PDC ≅ ∆ PAB [ASA postulate] ∴ PC = PA [Corresponding sides] ∴ P is the mid point AC