Question

please help, its literally urgent
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question—
construct a tangent to a circle of radius 2 cm from a point on the concentric circle of radius 5cm and measure its length by scale. Also verify the measurement by actual calculation

please answer in copy.
&
please write all the steps properly, please.,,​

Answer 1

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Steps of construction are:-

• 1) Draw a circle of radius 2cm with centre O.
• 2) Draw a concentric circle of radius 2.6cm centre O.
• 3) Mark point P on a larger circle.
• 4) Join PO. Make perpendicular bisector of PO. Let M be a mid point of PO.
• 5) Taking M as a centre and MO as a radius , draw a circle.
• 6) Let it intersect the given circle at points Q and R.
• 7) Join PQ and PR.

Therefore PQ and PR are the required tangents.

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Since △PQO is a right angle triangle.

By Pythagoras theorem,

PO² =PQ² +OQ²

2.6² =PQ² +2²

6.76=PQ² +4

PQ² =2.76

PQ=1.66

Similarly, PR=1.66

Length of the tangent is 1.66cm.

Answer 2

Step-by-step explanation:

p

1. draw a circle of radius 2cm with centre.

2. draw a concentric circle of radius 5cm centre O.

3. mark pont P on larger circle.

4. join PO . make perpendicular bisector of PO. let M be a mid point of PO.

5. taking M as centre and MO as radius , draw a circle.

6. let it intersect the given circle at point Q and R.

7. join PQ and PR are the required tangents .

since triangle PQO is a right angle triangle .

by pythagoras theorem ,