Math, asked by sindushriyam, 10 months ago

Please help...
Its urgent..

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Answered by aviswan60
1

Step-by-step explanation:

LHS = (cotA + secB)² - (tanB -cosecA)²

= cot²A + sec²B + 2cotAsecB - (tan²B + cosec²A - 2tanBcosecA

= cot²A + sec²B + 2cotAsecB - tan²B - cosec²A + 2tanBcosecA

= cot²A - cosec²A + sec²B - tan²B + 2cotAsecB + 2tanBcosecA

= -(cosec²A - cot²A) + (sec²B - tan²B) + 2(cotAsecB + tanBcosecA)

= -1 + 1 + 2(cotAsecB + tan.cosecA)

= 2(cotAsecB + tanBcosecA)

= RHS

HOPE IT HELPS

Answered by siprad649
0

Step-by-step explanation:

LHS = (cotA + secB)² - ( tan B - cosec A)²

= cot²A + 2cotAsecB + sec²B - tan²B + 2 tanBcosecA - cosec²A

= cot²A + 2cot A secB + 1 + 2tanBcosecA -1 - cot²A

= 2 cotAsecB + 2tanBcosecA

= 2 ( cotAsecB+ tanBcosecA)

= RHS

PROVED

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