Question

please help its urgent ​

Answer 1

Answer:

answer is beaker B

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Answer 2

Answer:

Hi,

1.Beaker B - Blue color

2. Beaker A - remain colorless

3. Beaker C - green color

Explanation:

When a Piece of copper added to the colorless solution of silver nitrate, it will give Copper nitrate solution and silver which is blue in color.

AgNO3 + Cu--------> Cu(NO3)2 + 2Ag

In the case of Beaker A(Zinc sulfate)

When copper added to the zinc sulfate solution, the color of the solution remain unchanged because copper cannot displace the Zinc. Zinc is more electronegative in nature, So no reaction takes place between copper and zinc sulfate to give CuSO4.(Blue color)

I hope it helps.