please help its urgent class 9th chapter circles find the value of x
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Join OC,OD and BC,
Angle COD=60°
Angle CBD=1/2 angle COD (theorem 10.8)
Angle CBD=30°
Angle ACB=90° (angle in the semicircle)
Angle BCE=180° - angle acb=90°
Angle CEB=90°-30°=60°
Therefore angle AEB(x)=60°
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